如何使用 MySQL COALESCE() 函数在列中的 NULL 位置插入值？

为了理解它，我们使用表“Employee”中的数据，其中 ID = 5 和 6 的 Salary=NULL，如下 –

mysql> Select * from Employee;
+----+--------+--------+
| ID | Name   | Salary |
+----+--------+--------+
| 1  | Gaurav | 50000  |
| 2  | Rahul  | 20000  |
| 3  | Advik  | 25000  |
| 4  | Aarav  | 65000  |
| 5  | Ram    | NULL   |
| 6  | Mohan  | NULL   |
+----+--------+--------+
6 rows in set (0.00 sec)

现在，以下查询将使用 COALESCE() 函数以及 UPDATE 和 WHERE 子句将值放在 NULL 的位置。

mysql> Update Employee set Salary = COALESCE(Salary,20000) where Id = 5;
Query OK, 1 row affected (0.09 sec)
Rows matched: 1 Changed: 1 Warnings: 0
mysql> Update Employee set Salary = COALESCE(Salary,30000) where Id = 6;
Query OK, 1 row affected (0.06 sec)
Rows matched: 1 Changed: 1 Warnings: 0
mysql> Select * from Employee;
+----+--------+--------+
| ID | Name   | Salary |
+----+--------+--------+
| 1  | Gaurav | 50000  |
| 2  | Rahul  | 20000  |
| 3  | Advik  | 25000  |
| 4  | Aarav  | 65000  |
| 5  | Ram    | 20000  |
| 6  | Mohan  | 30000  |
+----+--------+--------+
6 rows in set (0.00 sec)